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/* Search character in UTF-8 string.
Copyright (C) 1999, 2002, 2006-2007, 2009-2022 Free Software Foundation,
Inc.
Written by Bruno Haible <bruno@clisp.org>, 2002.
This file is free software.
It is dual-licensed under "the GNU LGPLv3+ or the GNU GPLv2+".
You can redistribute it and/or modify it under either
- the terms of the GNU Lesser General Public License as published
by the Free Software Foundation, either version 3, or (at your
option) any later version, or
- the terms of the GNU General Public License as published by the
Free Software Foundation; either version 2, or (at your option)
any later version, or
- the same dual license "the GNU LGPLv3+ or the GNU GPLv2+".
This file is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License and the GNU General Public License
for more details.
You should have received a copy of the GNU Lesser General Public
License and of the GNU General Public License along with this
program. If not, see <https://www.gnu.org/licenses/>. */
#include <config.h>
/* Specification. */
#include "unistr.h"
uint8_t *
u8_strrchr (const uint8_t *s, ucs4_t uc)
{
/* Calling u8_strlen and then searching from the other end would cause more
memory accesses. Avoid that, at the cost of a few more comparisons. */
uint8_t *result = NULL;
uint8_t c[6];
if (uc < 0x80)
{
uint8_t c0 = uc;
for (;; s++)
{
if (*s == c0)
result = (uint8_t *) s;
if (*s == 0)
break;
}
}
else
switch (u8_uctomb_aux (c, uc, 6))
{
case 2:
if (*s)
{
uint8_t c0 = c[0];
uint8_t c1 = c[1];
/* FIXME: Maybe walking the string via u8_mblen is a win? */
for (;; s++)
{
if (s[1] == 0)
break;
if (*s == c0 && s[1] == c1)
result = (uint8_t *) s;
}
}
break;
case 3:
if (*s && s[1])
{
uint8_t c0 = c[0];
uint8_t c1 = c[1];
uint8_t c2 = c[2];
/* FIXME: Maybe walking the string via u8_mblen is a win? */
for (;; s++)
{
if (s[2] == 0)
break;
if (*s == c0 && s[1] == c1 && s[2] == c2)
result = (uint8_t *) s;
}
}
break;
case 4:
if (*s && s[1] && s[2])
{
uint8_t c0 = c[0];
uint8_t c1 = c[1];
uint8_t c2 = c[2];
uint8_t c3 = c[3];
/* FIXME: Maybe walking the string via u8_mblen is a win? */
for (;; s++)
{
if (s[3] == 0)
break;
if (*s == c0 && s[1] == c1 && s[2] == c2 && s[3] == c3)
result = (uint8_t *) s;
}
}
break;
}
return result;
}
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