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authorJörg Frings-Fürst <debian@jff-webhosting.net>2018-07-15 18:00:09 +0200
committerJörg Frings-Fürst <debian@jff-webhosting.net>2018-07-15 18:00:09 +0200
commit82d1d89d2e68db56890c593a6428cdcbed1105f2 (patch)
tree7341711df7d1dc24bfec7b408e5b1fc3eeba7a10 /numlib/roots.c
parentd27d024c441a3912ac2959dff6183abf0e199d78 (diff)
parent711b90e2fe8e1b842c3181a6909af1e432fe0fdc (diff)
Merge branch 'feature/upstream' into develop
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+
+/*
+ * Roots3And4.c
+ *
+ * Utility functions to find cubic and quartic roots.
+ *
+ * Coefficients are passed like this:
+ *
+ * c[0] + c[1]*x + c[2]*x^2 + c[3]*x^3 + c[4]*x^4 = 0
+ *
+ * The functions return the number of non-complex roots and
+ * put the values into the s array.
+ *
+ * Author: Jochen Schwarze (schwarze@isa.de)
+ *
+ * Jan 26, 1990 Version for Graphics Gems
+ * Oct 11, 1990 Fixed sign problem for negative q's in SolveQuartic
+ * (reported by Mark Podlipec),
+ * Old-style function definitions,
+ * IsZero() as a macro
+ * Nov 23, 1990 Some systems do not declare acos() and cbrt() in
+ * <math.h>, though the functions exist in the library.
+ * If large coefficients are used, EQN_EPS should be
+ * reduced considerably (e.g. to 1E-30), results will be
+ * correct but multiple roots might be reported more
+ * than once.
+ * Apr 18, 2018 Reformat for inclusing in ArgyllCMS - GWG
+ *
+ * The authors and the publisher hold no copyright restrictions
+ * on any of these files; this source code is public domain, and
+ * is freely available to the entire computer graphics community
+ * for study, use, and modification. We do request that the
+ * comment at the top of each file, identifying the original
+ * author and its original publication in the book Graphics
+ * Gems, be retained in all programs that use these files.
+ *
+ */
+
+#include <math.h>
+#ifndef M_PI
+#define M_PI 3.14159265358979323846
+#endif
+
+/* epsilon surrounding for near zero values */
+#define EQN_EPS 1e-9
+#define IsZero(x) ((x) > -EQN_EPS && (x) < EQN_EPS)
+
+#define CBRT(x) ((x) > 0.0 ? pow((double)(x), 1.0/3.0) : \
+ ((x) < 0.0 ? -pow((double)-(x), 1.0/3.0) : 0.0))
+
+int SolveQuadric(double c[3], double s[2]) {
+ double p, q, D;
+
+ /* normal form: x^2 + px + q = 0 */
+ p = c[1] / (2 * c[2]);
+ q = c[0] / c[2];
+
+ D = p * p - q;
+
+ if (IsZero(D)) {
+ s[ 0 ] = - p;
+ return 1;
+ } else if (D < 0) {
+ return 0;
+ } else /* if (D > 0) */ {
+ double sqrt_D = sqrt(D);
+
+ s[0] = sqrt_D - p;
+ s[1] = - sqrt_D - p;
+ return 2;
+ }
+}
+
+
+int SolveCubic(double c[4], double s[3]) {
+ int i, num;
+ double sub;
+ double A, B, C;
+ double sq_A, p, q;
+ double cb_p, D;
+
+ /* normal form: x^3 + Ax^2 + Bx + C = 0 */
+ A = c[2] / c[3];
+ B = c[1] / c[3];
+ C = c[0] / c[3];
+
+ /* substitute x = y - A/3 to eliminate quadric term: */
+ /* x^3 +px + q = 0 */
+ sq_A = A * A;
+ p = 1.0/3 * (-1.0/3 * sq_A + B);
+ q = 1.0/2 * (2.0/27 * A * sq_A - 1.0/3 * A * B + C);
+
+ /* use Cardano's formula */
+ cb_p = p * p * p;
+ D = q * q + cb_p;
+
+ if (IsZero(D)) {
+ if (IsZero(q)) { /* one triple solution */
+ s[0] = 0.0;
+ num = 1;
+ } else { /* one single and one double solution */
+ double u = CBRT(-q);
+ s[0] = 2.0 * u;
+ s[1] = - u;
+ num = 2;
+ }
+ } else if (D < 0) { /* Casus irreducibilis: three real solutions */
+ double phi = 1.0/3 * acos(-q / sqrt(-cb_p));
+ double t = 2 * sqrt(-p);
+
+ s[0] = t * cos(phi);
+ s[1] = -t * cos(phi + M_PI / 3.0);
+ s[2] = -t * cos(phi - M_PI / 3.0);
+ num = 3;
+ } else { /* one real solution */
+ double sqrt_D = sqrt(D);
+ double u = CBRT(sqrt_D - q);
+ double v = -CBRT(sqrt_D + q);
+
+ s[0] = u + v;
+ num = 1;
+ }
+
+ /* resubstitute */
+ sub = 1.0/3.0 * A;
+
+ for (i = 0; i < num; i++)
+ s[i] -= sub;
+
+ return num;
+}
+
+
+int SolveQuartic(double c[5], double s[4]) {
+ double coeffs[4];
+ double z, u, v, sub;
+ double A, B, C, D;
+ double sq_A, p, q, r;
+ int i, num;
+
+ /* normal form: x^4 + Ax^3 + Bx^2 + Cx + D = 0 */
+ A = c[3] / c[4];
+ B = c[2] / c[4];
+ C = c[1] / c[4];
+ D = c[0] / c[4];
+
+ /* substitute x = y - A/4 to eliminate cubic term:
+ x^4 + px^2 + qx + r = 0 */
+ sq_A = A * A;
+ p = - 3.0/8 * sq_A + B;
+ q = 1.0/8 * sq_A * A - 1.0/2 * A * B + C;
+ r = - 3.0/256*sq_A*sq_A + 1.0/16*sq_A*B - 1.0/4*A*C + D;
+
+ if (IsZero(r)) {
+ /* no absolute term: y(y^3 + py + q) = 0 */
+
+ coeffs[0] = q;
+ coeffs[1] = p;
+ coeffs[2] = 0;
+ coeffs[3] = 1.0;
+
+ num = SolveCubic(coeffs, s);
+
+ s[num++] = 0;
+ } else {
+ /* solve the resolvent cubic ... */
+ coeffs[0] = 1.0/2.0 * r * p - 1.0/8.0 * q * q;
+ coeffs[1] = - r;
+ coeffs[2] = - 1.0/2.0 * p;
+ coeffs[3] = 1.0;
+
+ (void) SolveCubic(coeffs, s);
+
+ /* ... and take the one real solution ... */
+ z = s[0];
+
+ /* ... to build two quadric equations */
+ u = z * z - r;
+ v = 2 * z - p;
+
+ if (IsZero(u))
+ u = 0;
+ else if (u > 0)
+ u = sqrt(u);
+ else
+ return 0;
+
+ if (IsZero(v))
+ v = 0;
+ else if (v > 0)
+ v = sqrt(v);
+ else
+ return 0;
+
+ coeffs[0] = z - u;
+ coeffs[1] = q < 0 ? -v : v;
+ coeffs[2] = 1.0;
+
+ num = SolveQuadric(coeffs, s);
+
+ coeffs[0]= z + u;
+ coeffs[1] = q < 0 ? v : -v;
+ coeffs[2] = 1.0;
+
+ num += SolveQuadric(coeffs, s + num);
+ }
+
+ /* resubstitute */
+ sub = 1.0/4.0 * A;
+
+ for (i = 0; i < num; i++)
+ s[i] -= sub;
+
+ return num;
+}
+
+